Rus Articles Journal

# Once again about the great theorem of Fermat

at the time of Diophantus Y - odd (minus sign) and X - even met (plus) of number. They long talked and argued that Y is the man, and X - the woman. Without having come to the general opinion, they left, still were in separation. During this time the given rise Y considered everything as the man. Began to give them an image of God which nobody ever saw and did not notice. Recently they met again. X, given rise in even year Y which is given rise in odd year speaks: You changed in character, and appearance is invariable. After long separation of X kissed Y, felt in himself female essence - an image, breath and a face of the Goddess. From this point her appearance became surprisingly beautiful for a delighted look of Y. It was so formed the union of two contrasts - 5 couples: 0 and 9, 2 and 7, 4 and 5, 6 and 3, 8 and 1, i.e. X + Y = 9.
Turns out that we proved the great theorem of Fermat long ago (Diophantus the equation was solved), but were not known.
Integers + are formed by Z by means of 10 figures: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. They precisely to be divided into the 2nd integers + X - even, last right figures: 0, 2, 4, 6, 8 and + Y - odd, last right figures: 1, 3, 5, 7, 9, i.e. + X = + Y. Quantity of Y = 5 - odd and X = 5 - even numbers equally: Z = 10. Satisfies to the equation: (Z - X) X = (Z - Y) Y, and the decision + Z = + X + Y = + (X + Y).
Integers - Z consist of association of 2 integers - X - even and - Y - odd, and satisfies to the equation: (Z + X) X = (Z + Y) Y, and the decision - Z = - X - Y = - (X + Y).
we Will check decisions:
(Z - X) X = (Z - Y) Y, where Z = + X + Y, (+ X + Y - X) X = (X + Y-Y) Y; +XY = +XY.
(Z + X) X = (Z + Y) Y, where Z = - X - Y, (- X - Y + X) X = (- X - Y + Y) Y, - XY = - XY.
Means, + Z = + X + Y = + 10, + Z = +XY =25; - Z = - X - Y = - 10, Z = XY =25.
Digits consist of 5 odd and 5 odd numbers, and 2 - digit numbers 50 odd and 50 even. 2 - digit numbers begins with 00 and comes to an end 99 and there is 10th Art. 2 =10õ10 and to consider the 1st century = 100 years.
of Work of numbers is checked by division:
(Z - X) / (Z - Y) = Y/X =1 or (Z - Y) / (Z - X) = X/Y =1. (Z + X) / (Z + Y) = Y/X =1 or (Z + Y) / (Z + X) = X/Y =1.
From these the statement: Diophantus equation or great theorem of Fermat + (X Art. n + Y of the Art. n) = Zst. n is the solution of the equation (Zst. n - The X Art. n) the X Art. n = (Z of the Art. n - Y Art. n) Y of the Art. n, and - (The X Art. n + Y of the Art. n) = Zst. n is the solution of the equation (Zst. n + X Art. n) X Art. n = (Z of the Art. n + Y of the Art. n) Y of the Art. n.
passes Integers through each 3 categories into the following numeral system. Then 1000 =10st. 3 there are bases of integers. It is clear, that from these 500 - odd numbers, and 500 - even, then the equations have:
(10 Art. 3n + 10 Art. 3n) 10 Art. n = (10 Art. 3n +10 of the Art. 3n) 10 Art. 3n and the decision Z = - (500 x 10 Art. 3 (n - 1) + 500 x 10 Art. 3 (n - 1)) = - 10 Art. 3n;
(10 Art. 3n - 10 Art. 3n) 10 Art. 3n = (10 Art. 3n - 10 Art. 3n) 10 Art. 3n the decision Z = + (500õ10 Art. 3 (n - 1) + 500kh 10 Art. 3 (n - 1)) = +10st. 3n.
Of 1000 small identical sizes and color of cubes can form a big cube is rubik about 10. It is possible to make a big cube of 1 billion cubes is rubik about 1000.
has Any integer of n: - n and +n, +1/n and - 1/n, odd and even:
- (n + n + … + n) = - n of Art. 2; - (n x n x … x n) = - n of the Art. n; - (1 / n + 1/n + … + 1 / n) = - 1; - (1 / n x 1/n x … x1 / n) = - Art. n - n;
+ (n + n + … + n) = +n of Art. 2; + (n x n x … x n) = + n of the Art. n; + (1 / n + … +1 / n) = + 1; + (1 / n x 1/n x … x1 / n) = + Art. n - n.
Number 10 of the Art. 3n = 10 Art. n x 10 St. n x 10 Art. n, follow properties from here:
+ (10 Art. n + 10 Art. n + … + 10 Art. n) = + 10 Art. 2n; + (10 Art. n x 10 Art. n x … x 10 Art. n) = + 10 Art. n of the Art. (10 Art. n);
+ (10 Art. - n + 10 Art. - n + … + 10 Art. - n) = + 1; + (10 Art. - n x 10 Art. - n x … x 10 Art. - n) = + 10 Art. - Art. n (10 Art. - n);
- (10 Art. n + 10 Art. n + … + 10 Art. n) = - 10 Art. 2n; - (10 Art. n x 10 Art. n x … x 10 Art. n) = - 10 Art. n of the Art. (10 Art. n);
+ (10 Art. - n + 10 Art. - n + … + 10 Art. - n) = - 1; + (10 Art. - n x 10 Art. - n x … x 10 Art. - n) = - 10 Art. - Art. n (10 Art. - n);
we Will consider number 10 of the Art. 3n where n = 7, 10 Art. 3n = 10 Art. 21 =10st. 7 x 10 Art. 7 x 10 of Art. 7. It is rubik about 10000000 = 10st7=10 millions, consists from 1sekstillionov cubes. If to make dismantling of a rubik and to put cubes without intervals in one row or at each other, then we will receive horizontal or vertical pieces of length 1sekstillionov. At the same time each cube has a code - number 21 - the digit number is from 21 zero to 21 nine. With number - 10 Art. 7 we arrive as above. Now depending on the cube edge size, we will receive:
of Min: 1 m = 10 Art. 3 of mm = 10st6 ?R =10st. 9 nano =10st. 12piko =10st. 15 femto =10st. 18otto =10st. 21butto.
of Max: 1 km =10st. 3 m; 1 microns =10st. 6 m; 1gm =10st. 9 m; 1tm =10st. 12 m; 1pm =10st. 15 m; 1em =10st. 18 m; 1 N =10st. 21
Main constants: the meter, kilogram, degree, byte, percent, hour
Each integer is 1 (unit). Let`s consider the sums and works of units:
2+2 =4; 11õ11=121; 01+10 =;;;; 3+2=5; 111 h11=1221; 011õ10=0110; 3+3=6; 111õ111=12321: 011õ110 =;;;;;;
4 +3 =7; 1111õ111 =;;;;;;; 0111õ110 = 012210; 4+4=8; 1111+1111=1234321; 0111kh 1110=0123210; 5 + 4 = 9;
11111õ1111=12344321; 01111 x 1110 =0123443210; 5+5=10; 11111 x 11111 =123454321; 01111 x 11110 = 012343210; 6+5=1: 111111õ11111=1234554321; 011111+11110=0123443210;.
9+9=18; 9x9=81, 111111111x111111111=12345678987654321; 1+2+3+4+5+6+7+8+9+8+7+6+5+4+3+2+1=81
10+9=19; 10x9=90 1111111111x111111111 = 123456789987654321 sum of these figures are 90.
10 +10 =20; 10õ10=100, 0111111111 x 1111111110 = 0123456789876543210;
11 +10 =21; 01111111111 x 1111111110 = 01234567899876543210. If 2 rubik we deliver about 10 to
in the different ends of a piece of length 20 and we will give left a charge minus, and right plus, then they meet in the midpoint if in way there are no barriers, everyone passing 10 ways. Then we will give the charges of the same name, they will reach initial positions. At the same time the midpoint has number 0, and the ends 9. The first 01234567899876543210 is number of one created body, and female, and the second - addition to the first 98765432100123456789 - number of the man. we Know
that - rubik about 10 it is possible to make of 8 cubes rubik about 2. Length of an edge of a cube =20.
Is known that + (n of Art. 3 - n) always shares on +6, and - (n of Art. 3 - n) shares on - 6. We know that n of Art. 3 - n = (n - 1) n(n+1). It is the 3rd consecutive numbers (n - 1) n(n+1) where n - even, that shares on 2, (n - 1) and (n+1) odd, share on 3. Then (n - 1) n(n+1) always shares on 6. If n=0, (n - 1) n(n+1)= (-1)0(+1), n=20, (n - 1) n (n+1) = (19)(20)(21). Then 20 is zero, number 19 will be - 1, and 21 will be +1. we Say
that the circle makes 360 degrees. If to develop it, then we will receive a piece of length of 360 units. If in the ends of this piece we put a cube and we will give one charge plus, to another a charge minus, then everyone, passing 180 units of a way, meet in the midpoint at the same time, in way there are no barriers. Now we will give to cubes the charges of the same name, will reach initial positions, having passed the same ways.
of the Circle is divided radius into 6 parts, and with a diameter at 3. If to connect points of division pieces, then we will receive the correct hexagon. Let`s carry out diagonals, we will receive a cube in a sphere where the centers of a sphere and cube coincide, and the cube concerns in 8 points of a sphere, i.e. the circle is divided into 8 parts. These are crossings of two mutually perpendicular squares. If the sphere in a cube, then a sphere concerns in 6 points of a cube, and in the centers of the basis of a cube. Then length of diameter is equal to cube edge length. If on diameters of a sphere we carry out the planes - 3 mutually perpendicular squares, then we will receive rubik about 2 that the cubic system of coordinates is, and every 6th bases are a big square, the divided 4 =2x2 squares.
From here a cube in a sphere: 1 cube surround 7 cubes, i.e. equality is carried out: 6 n - 1 + 6n, it is also possible to make a big cube and rubik about 3. From 8 cubes - a big cube and rubik about 2. We know that 19 x 19 = 361. It is one square surround 360 squares and then one cube surround 360 cubes. From equality: 6 n - 1 + 6n, at n = 60 we will receive 360 - 1 + 360. If n = 61, then from 6 n - 1 + 6n we receive that 366 - 1 + 366. It is increase process around and reduction to 1.
the Cage is at the same time a cube in a sphere and a sphere in a cube, the size of length of an edge of a cube and length of radius of a sphere begins with 1butto = 10 Art. - 21 and 10 Art. 21m come to an end - it is the radius of Solar system.
Integers and alphabets become a source of disclosure of lie: usual, impudent and statistics.
we Will consider the equation of the X Art. 24 + Y of Art. 24 = Z Art. 24. We know that in the Greek and Latin alphabet 24 header and 24 capital letters what is reduced to a look: ABC... FGH... VWX + abc … fgh … vwY = 999 … 999 = Z where each letter is one of 10 figures: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and X- even, and Y- odd numbers are also carried out by X + Y = 9, A + a = 9, …, W + w = 9. To cover our Solar system with people, it is necessary 500kh10st. 21 women and 500kh10st. 21 men and to write down any 1000kh10st. 21 =..... 24 it is necessary 24 - digit number. It can be presented from 24 zero and on 24 nine. It is clear, that number 10 of Art. 24 consists 500kh10st. 24 odd and 500kh10st. 24 even numbers. Means, each person can appropriate the only code - number. Then each person live diamond of 24 nine of purity - test. Number 10 of St. 24 it is possible to present in the form two-submultiple column G = (X, Y, Z) where X - even, last right figures: 0, 2, 4, 6, 8, Y - odd, last right figures: 1, 3, 5, 7, 9 tops. Z - the edges connecting tops of X and Y at the same time are carried out equalities of X + by Y = Z, XY = Z. If Y = 500kh10st. 21 odd tops we will arrange in the decreasing order, X =500kh10st. 21 even tops in the increasing order, or on the contrary, we will receive paracombinations in two-submultiple to column G. It means that the sum of number odd and even 24 nine are equal. Conclusions: there is no
- death and in the Universe all created bodies live, the Mankind will forget concepts of an illness and death;
- are restored all ancestors and now the living 7 billion people in an ideal look - 24 nine of test, at the same time each person has 24 - digit number - a code, beginning 24 zero and including 24 nine.
to Clear organisms everyone restored and living now so that 360 x 10 St consisted. 21 cages, if this person woman. If the man, then 366 x 10 Art. 21 only from the cages, the weight of a cage of 10 Art. - 21 kg, the size of a cage of 10 Art. - 21 m, age of 25 years, and does not grow old further and is not ill - forever young and healthy. To calculate age of the person on a formula: [(4n)/3] +1, where n-years. The person is born in 9 months = ¾ years. +1 - life in a womb. Then the age of 30 years has 25 summer people. Each of them winners of a beauty contest and mind of the Universe. All equal, nobody deceives each other also superfluous to himself takes, one for all and all for one;
- Mankind in the development will pass to 7 steps at once: from millimeter, micro, nano, peak, femto, Otto on a buttotekhnologiya, also learns that he does not die and will live in the Universe as Gods;